BlackDevil
09-07-2008, 21:09
Hi
Ich hab grad ein Dickes Problem: Ich muss dort hinein einen Zeilenumbruch kriegen
\begin{equation*}
\left. \begin{aligned}
r(x)=&\frac{a_{11}}{x-\lambda_1}+\frac{a_{12}}{\left(x-\lambda_1\right)^2}+\ldots+\frac{a_{1n_1}}{\left(x-\lambda_1\right)^{n_1}}+\ldots\\
&+\frac{a_{r1}}{x-\lambda_r}+\frac{a_{r2}}{\left(x-\lambda_r\right)^2}+\ldots+\frac{a_{rn_r}}{\left(x-\lambda_r\right)^{n_r}}+\end{aligned}
\right\}\qquad\mathbb{R}
\left. \begin{aligned}
&+\frac{\alpha_{11}x+\beta_{11}}{x^2+A_1x+B_1}+\fra c{\alpha_{12}x+\beta_{12}}{\left(x^2+A_1x+B_1\righ t)^2}+\ldots+
\frac{\alpha_{1m_1}x+\beta_{1m_1}}{\left(x^2+A_1x+ B_1\right)^{m_1}}+\ldots\\
&+\frac{\alpha_{s1}x+\beta_{s1}}{x^2+A_sx+B_s}+\fra c{\alpha_{s2}x+\beta_{s2}}{\left(x^2+A_sx+B_s\righ t)^2}+\ldots+
\frac{\alpha_{sm_s}x+\beta_{sm_s}}{\left(x^2+A_sx+ B_s\right)^{m_s}}+\ldots\end{aligned}
\right\}\qquad\mathbb{C}
\end{equation*}
Der zweite Klammerblock beginnt beim zweiten Align
Grüße
Edit: so ginge es, dann sind sie aber am + nicht ausgerichtet
\begin{equation*}
\left. \begin{aligned}
r(x)=&\frac{a_{11}}{x-\lambda_1}+\frac{a_{12}}{\left(x-\lambda_1\right)^2}+\ldots+\frac{a_{1n_1}}{\left(x-\lambda_1\right)^{n_1}}+\ldots\\
&+\frac{a_{r1}}{x-\lambda_r}+\frac{a_{r2}}{\left(x-\lambda_r\right)^2}+\ldots+\frac{a_{rn_r}}{\left(x-\lambda_r\right)^{n_r}}+\end{aligned}
\right\}\qquad\mathbb{R}\end{equation*}
\begin{equation*}
\left. \begin{aligned}
&+\frac{\alpha_{11}x+\beta_{11}}{x^2+A_1x+B_1}+\fra c{\alpha_{12}x+\beta_{12}}{\left(x^2+A_1x+B_1\righ t)^2}+\ldots+
\frac{\alpha_{1m_1}x+\beta_{1m_1}}{\left(x^2+A_1x+ B_1\right)^{m_1}}+\ldots\\
&+\frac{\alpha_{s1}x+\beta_{s1}}{x^2+A_sx+B_s}+\fra c{\alpha_{s2}x+\beta_{s2}}{\left(x^2+A_sx+B_s\righ t)^2}+\ldots+
\frac{\alpha_{sm_s}x+\beta_{sm_s}}{\left(x^2+A_sx+ B_s\right)^{m_s}}+\ldots\end{aligned}
\right\}\qquad\mathbb{C}
\end{equation*}
Ich hab grad ein Dickes Problem: Ich muss dort hinein einen Zeilenumbruch kriegen
\begin{equation*}
\left. \begin{aligned}
r(x)=&\frac{a_{11}}{x-\lambda_1}+\frac{a_{12}}{\left(x-\lambda_1\right)^2}+\ldots+\frac{a_{1n_1}}{\left(x-\lambda_1\right)^{n_1}}+\ldots\\
&+\frac{a_{r1}}{x-\lambda_r}+\frac{a_{r2}}{\left(x-\lambda_r\right)^2}+\ldots+\frac{a_{rn_r}}{\left(x-\lambda_r\right)^{n_r}}+\end{aligned}
\right\}\qquad\mathbb{R}
\left. \begin{aligned}
&+\frac{\alpha_{11}x+\beta_{11}}{x^2+A_1x+B_1}+\fra c{\alpha_{12}x+\beta_{12}}{\left(x^2+A_1x+B_1\righ t)^2}+\ldots+
\frac{\alpha_{1m_1}x+\beta_{1m_1}}{\left(x^2+A_1x+ B_1\right)^{m_1}}+\ldots\\
&+\frac{\alpha_{s1}x+\beta_{s1}}{x^2+A_sx+B_s}+\fra c{\alpha_{s2}x+\beta_{s2}}{\left(x^2+A_sx+B_s\righ t)^2}+\ldots+
\frac{\alpha_{sm_s}x+\beta_{sm_s}}{\left(x^2+A_sx+ B_s\right)^{m_s}}+\ldots\end{aligned}
\right\}\qquad\mathbb{C}
\end{equation*}
Der zweite Klammerblock beginnt beim zweiten Align
Grüße
Edit: so ginge es, dann sind sie aber am + nicht ausgerichtet
\begin{equation*}
\left. \begin{aligned}
r(x)=&\frac{a_{11}}{x-\lambda_1}+\frac{a_{12}}{\left(x-\lambda_1\right)^2}+\ldots+\frac{a_{1n_1}}{\left(x-\lambda_1\right)^{n_1}}+\ldots\\
&+\frac{a_{r1}}{x-\lambda_r}+\frac{a_{r2}}{\left(x-\lambda_r\right)^2}+\ldots+\frac{a_{rn_r}}{\left(x-\lambda_r\right)^{n_r}}+\end{aligned}
\right\}\qquad\mathbb{R}\end{equation*}
\begin{equation*}
\left. \begin{aligned}
&+\frac{\alpha_{11}x+\beta_{11}}{x^2+A_1x+B_1}+\fra c{\alpha_{12}x+\beta_{12}}{\left(x^2+A_1x+B_1\righ t)^2}+\ldots+
\frac{\alpha_{1m_1}x+\beta_{1m_1}}{\left(x^2+A_1x+ B_1\right)^{m_1}}+\ldots\\
&+\frac{\alpha_{s1}x+\beta_{s1}}{x^2+A_sx+B_s}+\fra c{\alpha_{s2}x+\beta_{s2}}{\left(x^2+A_sx+B_s\righ t)^2}+\ldots+
\frac{\alpha_{sm_s}x+\beta_{sm_s}}{\left(x^2+A_sx+ B_s\right)^{m_s}}+\ldots\end{aligned}
\right\}\qquad\mathbb{C}
\end{equation*}